Trends

Determine A Linear Trend Line For Expected Freight Car Loadings.

a)Linear trend y = a+bxa = interceptb = slopex = time periody = forecast for demand for period xb = (sum xy – nbar{x}bar{y})/(sum x^{2}-nbar{x}^{2})a=bar{y}-bbar{x}n = no of peiodsbar{x}=sum x/n = the mean of the x valuesbar{y}=sum y/n = the mean of the y valueshttps://d2vlcm61l7u1fs.cloudfront.net/media%2Feaf%2Feafc365c-e796-4469-8a46-b7f682c3b780%2FphpOwiJOj.pngope b = (75713-(18*388.94*9.5))/(2109-(18*9.5*9.5)) = 19Intercept a = 388.94 – (9.5*19) = 208.44Y = 208.44 + 19xb)Forecast for week 20 and 21Y (x= 20) = 208.44 + 19* 20 = 588.44Y (x= 21) = 208.44 + 19* 21 = 607.44c)Y = 800800 = 208.44 + 19*xx = 31.13 weeks “Looking for a Similar Assignment? Get Expert Help at an Amazing Discount!”

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